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0=12x^2-44x+2
We move all terms to the left:
0-(12x^2-44x+2)=0
We add all the numbers together, and all the variables
-(12x^2-44x+2)=0
We get rid of parentheses
-12x^2+44x-2=0
a = -12; b = 44; c = -2;
Δ = b2-4ac
Δ = 442-4·(-12)·(-2)
Δ = 1840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1840}=\sqrt{16*115}=\sqrt{16}*\sqrt{115}=4\sqrt{115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{115}}{2*-12}=\frac{-44-4\sqrt{115}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{115}}{2*-12}=\frac{-44+4\sqrt{115}}{-24} $
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